I know that stopping power has been debated so much that it's like beating a horse who's been dead so long that barely the bones remain. But there's something that arouses my curiosity and perplexity.
It's the .455 Webley.
The Webley .455 revolver has been proven a very satisfying manstopper in over three quarters of a century of service.
It shoots a godawful chunk of lead, much like a good old catapult, at the speed a good old catapult would be capable of.
265 grains of lead, with a velocity of about 600 fps.
By comparison, the .45 ACP fires a 230 grains bullet (a respectable chunk of lead in itself) at the much more impressing velocity of 830-850 fps.
The contemporary 45 colt fired a 255 bullet up to 1000 fps.
BUT, al three cartridges seemed to perform equally well as for stopping power.
Per se, the 455 is capable of very modest penetration: about 18" in water, equivalent to 9", 10" inches in gelatin. We usually assume that 12" is minimum to get proper stopping power.
None the less, the .455 performed better than the 45 Colt at the Thompson Lagarde tests.
How can this very, very slow bullet, with so little penetration, have such a good stopping power?
Some ventured to say that the bullet's slow speed allowed the target to "feel more" he'd been hit.
Others said that it shattered bones better (and there may be a point here, if we compare this hypothesis with the principle on which the carronade was based: less shot speed, more shattering and splinters, instead of a cleanly cut hole).
Still... I wonder what may be the reason of such good performance.
Any opinions on the subject would be much appreciated.
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